determine the nuclear binding energy for Ir-187. Atomic mass of Ir-187=187.958830 g/mol

Question

(per nucleon)

dE=dmc(^2)

mass of proton= 1.00728 amu
mass of neutron=1.00866 amu

Answer 1

atomic number of Ir = # of protons = 77
so
mass of protons = 77.56056 amu
mass of neutrons = 110.9526 amu
total mass = 188.51316 amu

188.51316 - 187.95883 = .55433 grams/mol

= .00055433 kg/mol

* c^2 for energy /mol

.00055433 kg/mol * 9 * 10^16
= .00498897 *10^16 Joules/mol
divide by Avagadro # for Joules per nucleus
.00498897 *10^16 Joules/mol/(6*10^23)
= .005 * 10^-7
= 5 * 10^-4 Joules/nucleus

Answer 2

the answer is -4.43E-12 J/nucleons

Answer 3

I believe that answer should be -4.43E-13 J/nucleon.

0.55433 amu x 1.6605E-27 kg/amu x c^2 = ? for 187 nucleons. Divide by 187 for 4.42E-13 J/nucleon.

Answer 4

how u know to divide by 1.66E-27

Answer 5

so how do you solve it again?