<<the angle between the vector adn component>> which vector, which component?
Draw a polar chart, put the 35N force at 000, and the 20N @125.
Now call 000N, and 090 E
N vector components:
35+20cos125= ?23.5
E vector components
20 sin 125= ??16.4
Net result then is adding those two
magnitude:sqrt(23.5^2+16.4^2)=28.7
at an angle of arctan(16.4/23.5)=34.9 degrees from 090. I suspect that is where the 35 degrees came from, the true angle from 000 (N) would be 90-34.9 deg
Determine the net result of a 35 N force and a 20 N force acting on an object at an angle of 125° to each other, using components.
I know that when I draw the vectors, I use parallelogram law to determine the complimentary angle, and I got 55degrees. However, on the answers, it says that the angle between the vector and its component was 35degrees. Where did this 35degrees come from?
1 answer
1 answer