To have an infinite amount of solutions, the equation must be equivalent to zero. Thus, we need to determine the values of "?" and "?" that make 2(6x + 7) = 3x + ?x equivalent to zero.
Expanding the left side of the equation, we get 12x + 14. Setting this equal to zero, we have 12x + 14 = 0. Simplifying, we subtract 14 from both sides to isolate the variable x: 12x = -14. Lastly, we divide both sides by 12 to solve for x: x = -14/12.
Therefore, no matter the values of "?" and "?", the equation can never be equivalent to zero and, thus, there are no missing values that would make it have an infinite amount of solutions.
Determine the missing values that would make this equation have infinite amount of solutions
2(6x+7)=3x+?x=?
1 answer
1 answer