Determine the missing values that would make this equation have infinite amount of solutions. Both answers will be integers. 2(6x+7)=−4x+ x+

Answer 1

To have an infinite amount of solutions, the equation should result in a true statement regardless of the value of x.

Let's simplify the equation:
2(6x+7) = -4x + x

Distribute the 2 on the left side:
12x + 14 = -4x + x

Combine like terms:
12x + 14 = -3x

Add 3x to both sides:
15x + 14 = 0

Subtract 14 from both sides:
15x = -14

Divide both sides by 15:
x = -14/15

Therefore, the missing values for x that would make the equation have an infinite amount of solutions are x = -14/15 or x = -0.933333...

Answer 2

Determine the missing values that would make this equation have infinite amount of solutions. Both answers will be integers. 2(6x+7)=−4x+_x +_

Answer 3

To have an infinite number of solutions, the coefficients of x should cancel out on both sides of the equation. That means the coefficient of x on the right side of the equation should be the negative sum of the coefficients of x on the left side.

Given the equation: 2(6x+7) = -4x + _x + _

Let's determine the values that would make the equation have an infinite number of solutions:

On the left side of the equation, the x term has a coefficient of 0 since 2(6x) cancels out the x term on the right side.

So, the missing values for x would be:
2(6x+7) = -4x + 0x + 0

Simplifying further:
12x + 14 = -4x

Combine like terms:
12x + 4x + 14 = 0

Add 4x to both sides:
16x + 14 = 0

Subtract 14 from both sides:
16x = -14

Divide both sides by 16:

x = -14/16

x = -7/8

Therefore, the missing values for x that would make the equation have an infinite amount of solutions are x = -7/8 or x = -0.875.