Determine the missing coordinate of the point (4/7,y) that lies on the graph of the unit circle in quadrant IV. Please show the steps because I need to solve more. Thank you.

Answer 1

x^2 + y^2 = 1

16/49 + y^2 = 49/49

y^2 = 33/49

y = +/- sqrt (33) /7

so since in Q IV where y is negative
(4/7, -sqrt(33)/7 )