Determine the minimum electric potential difference (in volts) that must be applied to accelerate an α-particle so that on interaction with a hydrogen atom, a ground state electron will be excited to n = 6.

Answer 1

E=qV
E=-k((1/nf^2)-(1/ni^2))
V=(-k/q)(1/25-1/1)*(24/25)
V=(2.18e-18/1.602e-19 J)*(24/25)
V=13.1 Volt
13.1 eVolt