I will do the first one, you do the second in the same way
a) y = 2x^3 - 9x^2 , -2 ≤ x ≤ 4
dy/dx = 6x^2 - 18x
= 0 for a max/min
6x(x-3) = 0
x = 0 or x = 3, both are within our given domain
if x = 0 , y = 0
if x = 3 , y = 56 - 81 = -27
so the max is 0 and the min is -27
Determine the maximum and minimum of each function on the given interval.
a) ���� = 2x^3�� − 9x^2�� ,−2 ≤ x� ≤ 4
b) ���� = 12x� − x^3�� , � x∈ �[−3,5]
2 answers
should have checked the end points
if x = -2 , y = -16 - 36 = -52
if x = 4 , y = -16
revised answer:
the max is 0 and the min is -52 within the given domain.
if x = -2 , y = -16 - 36 = -52
if x = 4 , y = -16
revised answer:
the max is 0 and the min is -52 within the given domain.