Asked by Leah
Determine the mass of CuSO4 • 5H2O needed to prepare 100.00 mL of 0.65000 M copper sulfate solution.
Answers
Answered by
DrBob222
From this post I assume you want to prepare CuSO4 solution and not CuSO4.5H2O.
How many mols CuSO4 do you need? That's M x L = 0.65000 x 0.100 = 0.06500
grams CuSO4 = mols x molar mass CuSO4 = ?
But you want to weigh CuSO4.5H2O so how do you handle that?
Use the mass shown by ? x (molar mass CuSO4.5H2O/molar mass CuSO4) = this you weigh out, place it in a 100 mL volumetric flask, add a a little distilled water, swirl until all of the CuSO4.5H2O is dissolve, then add distilled to the mark on the volumetric flask, stopper, mix thoroughly, label. Done.
How many mols CuSO4 do you need? That's M x L = 0.65000 x 0.100 = 0.06500
grams CuSO4 = mols x molar mass CuSO4 = ?
But you want to weigh CuSO4.5H2O so how do you handle that?
Use the mass shown by ? x (molar mass CuSO4.5H2O/molar mass CuSO4) = this you weigh out, place it in a 100 mL volumetric flask, add a a little distilled water, swirl until all of the CuSO4.5H2O is dissolve, then add distilled to the mark on the volumetric flask, stopper, mix thoroughly, label. Done.
Answered by
Leah
Would it be 16.229g?
Answered by
DrBob222
That looks good to me.
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