mols Al = grams/molar mass = ?
mols KOH = M x L = ?
Use the coefficients in the balanced equation to convert mols Al to mols of the product.
Do the same for the mols KOH to mols of the product.
It is likely that the two values for mols product will not agree; the correct value in limiting reagent problems is ALWAYS the smaller value and the reagent responsible for that result is the limiting reagent.
Use the smaller value and convert to grams alum. g = mols x molar mass = ?
Determine the limiting reactant for this reaction if 3.027 grams of Aluminum are reacted with 60.00
mL of a solution that is 6 M KOH. Determine the amount of KAl(SO4)2•12 H2O that can be produced from this reaction. Molar mass Alum = 474 g/mol
2 Al (s) + 2 KOH (aq) + 22 H2O (l) + 4 H2SO4 (aq) → 2 KAl(SO4)2 •12 H2O (s) + 3 H2 (g)
1 answer
1 answer