Determine the initial value and the rate of change of the linear function given in the graph. (1 point) The initial value is , and the rate of change is
1 in wrong
11 answers
Unfortunately, there is no given information or a graph provided to determine the initial value and rate of change of the linear function. Can you please provide more details or specify what graph you are referring to?
0,0 2,2
Given the points (0,0) and (2,2), we can find the equation of the linear function in slope-intercept form (y = mx + b) to determine the initial value and rate of change.
First, let's find the rate of change or slope (m) using the formula: m = (y2 - y1)/(x2 - x1)
m = (2 - 0)/(2 - 0) = 2/2 = 1
So, the rate of change is 1.
Next, let's find the initial value or y-intercept (b). We can substitute the coordinates of one of the points (- 0,0 -) into the equation y = mx + b and solve for b.
0 = 1*0 + b
0 = 0 + b
b = 0
So, the initial value is 0.
Therefore, the linear function can be written as y = 1x + 0 or simply y = x. The initial value is 0, and the rate of change is 1.
First, let's find the rate of change or slope (m) using the formula: m = (y2 - y1)/(x2 - x1)
m = (2 - 0)/(2 - 0) = 2/2 = 1
So, the rate of change is 1.
Next, let's find the initial value or y-intercept (b). We can substitute the coordinates of one of the points (- 0,0 -) into the equation y = mx + b and solve for b.
0 = 1*0 + b
0 = 0 + b
b = 0
So, the initial value is 0.
Therefore, the linear function can be written as y = 1x + 0 or simply y = x. The initial value is 0, and the rate of change is 1.
1 is wrong
Apologies for the incorrect response. Let's reevaluate the points (0,0) and (2,2) to find the correct initial value and rate of change.
Using the formula for rate of change (slope):
m = (y2 - y1)/(x2 - x1)
m = (2 - 0)/(2 - 0) = 2/2 = 1
The rate of change or slope is 1.
To find the initial value or y-intercept, we can substitute the coordinates of one of the points into the equation y = mx + b.
Using the point (0,0):
0 = 1(0) + b
0 = 0 + b
b = 0
The initial value is 0.
Therefore, the linear function can be written as y = 1x + 0 or simply y = x. The initial value is 0, and the rate of change is 1.
Using the formula for rate of change (slope):
m = (y2 - y1)/(x2 - x1)
m = (2 - 0)/(2 - 0) = 2/2 = 1
The rate of change or slope is 1.
To find the initial value or y-intercept, we can substitute the coordinates of one of the points into the equation y = mx + b.
Using the point (0,0):
0 = 1(0) + b
0 = 0 + b
b = 0
The initial value is 0.
Therefore, the linear function can be written as y = 1x + 0 or simply y = x. The initial value is 0, and the rate of change is 1.
Determine the initial value and the rate of change of the linear function as given in the graph. (1 point) The initial value is , and the rate of change is .
Apologies for the confusion. Without a provided graph or any specific values, it is not possible to determine the initial value or the rate of change of the linear function. Please provide more details or specify the graph you are referring to.
-3,2.5 0,1 2,1
To determine the initial value and rate of change of the linear function given the points (-3, 2.5), (0, 1), and (2, 1), we can use the slope-intercept form of a linear equation, y = mx + b.
Step 1: Calculate the rate of change or slope (m):
m = (y2 - y1)/(x2 - x1)
m = (1 - 2.5)/(0 - (-3))
m = (-1.5)/(3)
m = -0.5
Therefore, the rate of change is -0.5.
Step 2: Determine the initial value or y-intercept (b).
We can substitute one of the points' coordinates into the equation y = mx + b and solve for b. Let's use the point (0, 1):
1 = -0.5(0) + b
1 = 0 + b
b = 1
Therefore, the initial value is 1.
So, the linear function can be written as y = -0.5x + 1. The initial value is 1, and the rate of change is -0.5.
Step 1: Calculate the rate of change or slope (m):
m = (y2 - y1)/(x2 - x1)
m = (1 - 2.5)/(0 - (-3))
m = (-1.5)/(3)
m = -0.5
Therefore, the rate of change is -0.5.
Step 2: Determine the initial value or y-intercept (b).
We can substitute one of the points' coordinates into the equation y = mx + b and solve for b. Let's use the point (0, 1):
1 = -0.5(0) + b
1 = 0 + b
b = 1
Therefore, the initial value is 1.
So, the linear function can be written as y = -0.5x + 1. The initial value is 1, and the rate of change is -0.5.
What was an underlying source of tension in westward expansion during the 1850s? (1 point) Responses The inflation of goods The inflation of goods A sharp decrease in population A sharp decrease in population Whether newly added territories should allow slavery Whether newly added territories should allow slavery Disagreement over whether the economy of new territories be based on farming or factories
The underlying source of tension in westward expansion during the 1850s was the disagreement over whether the newly added territories should allow slavery.