Determine the initial acceleration of a 1 kg solid aluminum chunk (density = 2,700 kg/m3) released from rest by a diver 10 m under the ocean.

Answer 1

Assume water is about 1000 kg/m^3
Force up = 1000 * V *g
Force down = m g = 2700 * V * g
so V = 1/2700

force up = (10/27)g
force down = 1 g
net force down = (1-10/27) g

F = m a
(1 -10/27) g = 1 a
a = 9.81 *(17/27) down

Answer 2

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