Using the lens equation:
1/f = 1/di + 1/do
where f is the focal length, di is the image distance, and do is the object distance
Plugging in the values:
1/24 = 1/di + 1/48
Solving for di:
di = 32.0 cm
This means the image is formed 32.0cm away from the lens.
Using the magnification equation:
m = hi/ho = -di/do
where hi is the image height, ho is the object height
Plugging in the values:
m = hi/50.0 = -32.0/48.0
Solving for hi:
hi = -21.3 cm
The negative sign indicates that the image is inverted. The image height is 21.3 cm.
Determine the image distance and image height for a 50.0cm tall object placed 48.0cm from a converging lens having a focal length of 24.0cm.
1 answer
1 answer