dETERMINE the horizontal force needed to accelerate a 50 kg grocery cart from rest to 0.90 m/s in 2.8s if the coefficient of friction between the cart and the floor is 0.20?

Answer 1

a = (.90 -0)/2.8

weight = m g = 50 (9.81)

friction force = .2 * 50 (9.81)

F - .2*50(9.81) = 50 (.9)/2.8

Answer 2

did the sign * is for multplication?

Answer 3

yes * means "times"