πr^2h = 512
So, h = 512/(πr^2)
area a = 2πr^2 + 2πrh
= 2πr^2 + 2πr (512)/(πr^2)
= 2πr^2 + 1024/r
Assuming you have calculus, we see that
da/dr = 4πr - 1024/r^2
da/dr=0 when r = 4∛(4/π)
Now you can find h.
Determine the height and radius of cylinder of volume 512 cm3 which has the least total surface area
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