Determine the heat evolved (in kJ and in J) when 10.0 g of NH3(g) are created.

Show all units and conversion factors.

10.0 gNH3 (1 mole nh3/17.0 g nh3)(-46.11 kj/1 mol nh3) = 23.11 kj

-27.12 kj (1000j/1kj) -27,120

Is this correct?

1 answer

1a.You must have punched in the wrong numbers. 10.0*1/17)*46.11 is not 23.11
1b. If you use -46.11 then the sign should stay in the answer.

2. I would buy the second part if you added an equal sign.