To find the greatest common factor (GCF) of the expression \( 24x^3y^4 - 15xy^2 - 36x^2y^3 \), we can first factor each term separately.
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Coefficients: Identify the coefficients of each term:
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The coefficients are \( 24 \), \( -15 \), and \( -36 \).
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The GCF of the coefficients:
- Factors of \( 24 \): \( 1, 2, 3, 4, 6, 8, 12, 24 \)
- Factors of \( 15 \): \( 1, 3, 5, 15 \)
- Factors of \( 36 \): \( 1, 2, 3, 4, 6, 9, 12, 18, 36 \)
The common factors are \( 1 \) and \( 3 \), hence the GCF of the coefficients is \( 3 \).
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Variables: Now, let's find the GCF of the variable parts.
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For \( x \):
- The exponents in each term are \( 3 \) (in \( 24x^3y^4 \)), \( 1 \) (in \( -15xy^2 \)), and \( 2 \) (in \( -36x^2y^3 \)).
- The GCF for \( x \) is \( x^{\min(3, 1, 2)} = x^1 = x \).
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For \( y \):
- The exponents in each term are \( 4 \) (in \( 24x^3y^4 \)), \( 2 \) (in \( -15xy^2 \)), and \( 3 \) (in \( -36x^2y^3 \)).
- The GCF for \( y \) is \( y^{\min(4, 2, 3)} = y^2 \).
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Combining: Now, combine the GCF of the coefficients with the GCF of the variables: \[ \text{GCF} = 3xy^2 \]
So, the greatest common factor of \( 24x^3y^4 - 15xy^2 - 36x^2y^3 \) is \(\boxed{3xy^2}\).