Determine the grams of solute required to prepare 507 ml of a 2.75M NaF solution

Answer 1

To determine the grams of solute required, we need to use the formula:

moles of solute = Molarity x Volume (in liters)

First, we need to convert the volume from milliliters to liters:

507 ml = 507/1000 = 0.507 L

Then we can use the formula to calculate the moles of NaF:

moles of NaF = 2.75 M x 0.507 L = 1.39425 moles NaF

Now we can calculate the grams of NaF by multiplying the moles by the molar mass of NaF. The molar mass of NaF is approximately 41 grams/mol.

grams of NaF = 1.39425 moles NaF x 41 g/mol = 57.08725 grams NaF (rounded to the nearest hundredth)

Therefore, approximately 57.09 grams of NaF are required to prepare 507 ml of a 2.75M NaF solution.