Ask a New Question

determine the first three terms of the erithmetic progression of which the 7th term is 3 and the 12th term is -3?

1 answer

#1: a+6d=3
#2: a+11d=-3
subtract them
-5d = 6
d = -6/5

back into a+6d=3
a + 6(-6/5) = 3
a = 3 + 36/5 = 51/5

first three terms are:
51/5 , 9 , 29/5

Ask a New Question or answer this question.

Similar Questions

The 5th and 10th terms of an arithmetic progression are 18 and -2 respectively.(a) Find the common difference and the first
1. 1 answer
The third term of a geometric progression of positive terms is 18 and the fifth term is 162Find the common ration and the first
1. 1 answer
In an infinite geometric progression with positive terms and with a common ratio |r|<1, the sum of the first three terms is
1. 1 answer
The first,third and seventh term of an arithmetic progression form three consecutive terms of a geometric progression. If the
1. 3 answers

more similar questions