Determine the final temperature when 100 g of water absorbs 1000 J of thermal energy, given that the initial temperature of the water is 20.0°C. The theoretical specific heat capacity of water is 4.19 J/g·°C. Show your work below.

Answer 1

2.40

Answer 2

22.4

Answer 3

The final temperature of the water can be determined using the formula:

Q = mcΔT

where Q is the thermal energy absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Substituting the given values, we have:

1000 J = (100 g) x (4.19 J/g·°C) x ΔT

Simplifying, we get:

ΔT = 1000 J / (100 g x 4.19 J/g·°C)

ΔT = 2.391°C

The change in temperature is positive, indicating that the water has gained heat. To find the final temperature, we add the change in temperature to the initial temperature:

Final temperature = 20.0°C + 2.391°C

Final temperature = 22.391°C

Therefore, the final temperature of the water is 22.391°C (rounded to three decimal places).