determine the final temp when 45.8 g of aluminum at -5.2 degrees C is added to a mixture of 45.0 grams of ice at 0.00 degrees C and 2000.0 g of water at 95.0 degrees C.

Answer 1

First, assume the final temp will be between 0 and 95. If this is not the case, you will get an odd answer.

The sum of all the heats gained will be zero (some will be negative, heat lost).

Heat gained by Al+ heatmeltingice+heat heating ice water + heat from hot water=0
45.8*Calum*(Tf-(-5.2))+45*Hfice+45*cwater(Tf-0)+2000*cwater*(Tf-95)=0
solve for Tf