Determine the equilibrium constant, Keq, for the reaction
5.3 10–19
18.30
1.7 1054
1.9 1018
5.7 10–55
i have tried this but get the wrong answer. i have the half-rxn and fugured out E=0.536. then used eq
dG=-nFE, followed by dG=-RTInK. PLS HELP
2 answers
I responded to this recently by saying you needed to clarify what these numbers are. I have no idea what they mean. That may explain why no one has answered you because no one can figure out to what these numbers refer.
right then, numbers are-
Br2 + 2e- = 2Br E=1.065V
I2(s)+ 2e- = 2I- E=0.536V
i have placed both these numbers into eq- Ecell= Ered(cathode)-Ered(anode)
but for every combination, using the before mentioned eq, i cannot get any answers that they offer.
If E i get either +/- 1.601 or +/- 0.529. these put into eq 2- dG=-nFE (n=moles, F-96485, E=? Above)
then putting that into eq 3- dG=-RTInK (with R=8.314, and T=298) to find K. I just cant get their answers!?
Br2 + 2e- = 2Br E=1.065V
I2(s)+ 2e- = 2I- E=0.536V
i have placed both these numbers into eq- Ecell= Ered(cathode)-Ered(anode)
but for every combination, using the before mentioned eq, i cannot get any answers that they offer.
If E i get either +/- 1.601 or +/- 0.529. these put into eq 2- dG=-nFE (n=moles, F-96485, E=? Above)
then putting that into eq 3- dG=-RTInK (with R=8.314, and T=298) to find K. I just cant get their answers!?