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1. First, you need to find the slope of the given line (3x+2y=6).
2. Then, once you find the slope, determine the perpendicular slope.
3. Once you have the perpendicular slope, determine the equation for a line which goes through (-6, -2).
If you have any questions about any of these steps, please feel free to reply to this thread.
Thanks!
Leo
Determine the equations of a straight line passing through (-6;-2) and pependicular to 3x+2y=6
3 answers
P(-6,-2).
3x + 2y = 6
m1 = -A/B = -3/2
m2 = -(-2/3) = 2/3 = Negative reciprocal
Y = mx + b = -2
2x/3 + b = -2
(2*-6)/3 + b = -2
-4 + b = -2
b = 2.
Eq: Y = 2x/3 + 2
3x + 2y = 6
m1 = -A/B = -3/2
m2 = -(-2/3) = 2/3 = Negative reciprocal
Y = mx + b = -2
2x/3 + b = -2
(2*-6)/3 + b = -2
-4 + b = -2
b = 2.
Eq: Y = 2x/3 + 2
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