Determine the equation of the tangent line to the curve y = (2x^2 - 1) (2x^2 - 2x +1) when x = 2

Answer 1

y(2) = 35
y' = 2(8x^3 - 6x^2 + 1)
y'(2) = 82
so the line has equation
y-35 = 82(x-2)