Asked by bontle
Determine the equation of a straight line passing through (3,-1) and parallel to 2y-6x=1
Answers
Answered by
Reiny
easiest way:
since it is parallel it must differ only in the constant
let the equation be
2y - 6x = x
at (3,-1)
-2 - 18 = c
c = -20
2y - 6x = -20
or
3x - y = 10
since it is parallel it must differ only in the constant
let the equation be
2y - 6x = x
at (3,-1)
-2 - 18 = c
c = -20
2y - 6x = -20
or
3x - y = 10
Answered by
Henry
(3,-1).
-6x + 2y = 1
Parallel lines have equal slopes:
m1 = m2 = -A/B = 6/-2 = -3
Y = mx + b = -1
-3*3 + b = -1
b = 8
Eq: Y = -3x + 8
-6x + 2y = 1
Parallel lines have equal slopes:
m1 = m2 = -A/B = 6/-2 = -3
Y = mx + b = -1
-3*3 + b = -1
b = 8
Eq: Y = -3x + 8
Answered by
Henry
CORRECTION:
m1 = m2 = -A/B = 6/2 = 3
Y = mx + b = -1
3*3 + b = -1
b = -10
Eq: Y = 3x - 10
m1 = m2 = -A/B = 6/2 = 3
Y = mx + b = -1
3*3 + b = -1
b = -10
Eq: Y = 3x - 10
Answered by
nallz
lebo
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