Determine the distance traveled by a particle whose initial velocity is 48km/h. The particle accelerate uniformly at Tate of 1.8m/s and attained a velocity of 72km/h?

Answer 1

Vo = 48km/h = 48,000m/3600s = ___ m/s.
V = 72km/h =

V^2 = Vo^2 + 2a*d. Solve for d.