Determine the discrimination of x2+x+1=0 and discribe the nature of its roots

Answer 1

The coefficients are:

a = 1 , b = 1 , c = 1

Discriminant:

D = b² - 4 ∙ a ∙ c = 1² - 4 ∙ 1 ∙ 1 = 1- 4 = - 3

D < 0 so the quadratic has two complex conjugate solutions.