determine the correct answers to the calculation shown below to the correct number of significant figures?
a. (32.453)(34.23+1.17)/(2.26-1.811)(0.00378)=9.671716784=9.7
b. (3.23+0.0018)=3.2318=3.2
c. (82.97-0.012)/(1.100)(21.9)=1651.618364
2 answers
would you tell me please are the answers corect?
a.
Assuming I understand the calculation as presented as I don't get the same numerical answers.
(32.453)(34.23+1.17)/(2.26-1.811)(0.00378)=
(32.453)(35.40)/(0.50)(0.00378)
(retaining the least precise decimal places)
the next step will need to retain the sig figs. The least sig figs is two (0.50)
(32.453)(35.40)/(0.50)(0.00378)
=607849
which is 6.1 x 10^5 to two sig figs
b.
(3.23+0.0018)=3.2318=3.23
the least precise is the two dp in 3.23
c. (82.97-0.012)/(1.100)(21.9) =
(82.96)/(1.100)(21.9)
For the next step the least number of significant figures is three (21.9)
(82.96)/(1.100)(21.9) =
3.44 to three sig figs
Assuming I understand the calculation as presented as I don't get the same numerical answers.
(32.453)(34.23+1.17)/(2.26-1.811)(0.00378)=
(32.453)(35.40)/(0.50)(0.00378)
(retaining the least precise decimal places)
the next step will need to retain the sig figs. The least sig figs is two (0.50)
(32.453)(35.40)/(0.50)(0.00378)
=607849
which is 6.1 x 10^5 to two sig figs
b.
(3.23+0.0018)=3.2318=3.23
the least precise is the two dp in 3.23
c. (82.97-0.012)/(1.100)(21.9) =
(82.96)/(1.100)(21.9)
For the next step the least number of significant figures is three (21.9)
(82.96)/(1.100)(21.9) =
3.44 to three sig figs
0 answers