When a point A(x, y) is reflected over the x-axis, the y-coordinate of the point changes sign, while the x-coordinate remains the same. Therefore, the coordinates of the reflected point A' will be (x, -y).
Since A' is located in quadrant II, this means that A' will have a negative x-coordinate and a positive y-coordinate. Consequently, if you have the original coordinates for A (in quadrant II), they would be negative for the x-value and positive for the y-value.
For example, if the coordinates for point A were (-a, b) (where a > 0 and b > 0), after reflecting over the x-axis, the coordinates of A' would be (-a, -b). Notably, A' would then be located in quadrant III since the x-coordinate is negative and the y-coordinate is also negative.
If you're looking for a point A' specifically in quadrant II after reflecting over the x-axis, that wouldn't be possible since the reflection over the x-axis does not yield a point in quadrant II—it would instead yield a point in quadrant III.
In summary, if you reflect a point in quadrant II over the x-axis, the resulting point will always fall in quadrant III. If you have specific coordinates for A, I can assist you further!
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