Determine the convergence or divergence:

An=(-1)^n(n/(n+1))

2 answers

A(n+1)= -1^(n+1) (n+1)/(n+2)

A(n+1)/An= -1* 1/n * 1/(n+2) which as n >> large, converges to zero.
I would reccomend you to open your book and spend a few minutes ;)