Determine the concentration of iron in an aqueous solution containing 0.2810 grams of Fe(NH4)2(SO4)2 per liter of solution. Express the concentration in mg/dl.

Answer 1

I am sorry. I meant mg/L

Answer 2

0.2810g Fe(NH4)2(SO4)2 x (1000 mg/g) x [1 mol Fe/1 mol Fe(NH4)2(SO4)2] x (1 mol Fe(NH4)2(SO4)2/284g) x (55.85g Fe/1 mol Fe) = ?

Or without all the mishmash it is
0.2810 x (atomic mass Fe/molar mass Fe(NH4)2(SO4)2) x 1000 = 0.2810 x (55.85/284) x 1000 = ?

Answer 3

Thank you DrBob222! You saved my day.