a. (k + 9)^2 = 71
Take the square root of both sides to solve for k + 9:
k + 9 = ±√71
Subtract 9 from both sides to solve for k:
k = -9 ± √71
Therefore, the approximate solutions for k are:
k ≈ -9 + √71 and k ≈ -9 - √71
b. (6 - p)^2 = 47
Take the square root of both sides to solve for 6 - p:
6 - p = ±√47
Subtract 6 from both sides to solve for p:
-p = -6 ± √47
Divide by -1 to solve for p:
p = 6 ± √47
Therefore, the approximate solutions for p are:
p ≈ 6 + √47 and p ≈ 6 - √47
Determine the approximate solutions to each of the given equations. Show your work.
a.(k + 9)^2= 71
b. (6 - p)^2=47
1 answer