According to the equation you get 114.6 kJ/mol or 229.2 kJ/2 mols or 222.9 kJ/92 g so use that as your conversion factor as follows:
222.9 kJ x (12600 g/92 g) = ?
Determine the amount of heat (in kJ) given off when 1.26 x 104 g of NO2 are produced according to the equation:
2NO(g) + O2(g) → 2NO2(g) ΔH = -114.6 kJ/mol
3 answers
oops. I transposed some numbers. The following should fix that.
According to the equation you get 114.6 kJ/mol or 229.2 kJ/2 mols or 229.2 kJ/92 g so use that as your conversion factor as follows:
229.2 kJ x (12600 g/92 g) = ?
According to the equation you get 114.6 kJ/mol or 229.2 kJ/2 mols or 229.2 kJ/92 g so use that as your conversion factor as follows:
229.2 kJ x (12600 g/92 g) = ?
Determine the amount of heat (in kJ) given off when 1.26 3 10 4 g of NO 2 are 2NO(g)+O2(g) to 2NO2(g)