The normal force of the box is mg*cosTheta.
The force of gravity down the plane is mg*SinTheta
so the net force down the plane is
forcegravity-friction
because the friction is zero, then you don't have to worry about normal force in the motion.
Netforce=mass*acceleration
or acceleration= mgSinTheta/m= g*sinTheta
Determine the acceleration and normal force of system below. Assume no friction, the mass equal to 10.0 kg and the angle equal to 60.0 degrees. Assume gravity equals 9.8 m/s/s.
The picture looks like a right triangle with a box sliding down it.
I am a 9th grader in conceptual physics, so the calculus is already provided for us. So if you could solve this without calculus, that would be great!
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