clearly a simple parabola
f ' (x) = 2(1-x) = 0 for a max/min
x=1
f(1) = (1-1)^2 = 0
endpoints:
f(0) = (-1)^2 = 1
f(2) = (162 = 1
parabola opens up, so the minimum is 0 when x = 1
or
(the vertex is (1,0) )
You have posted several of these rather straightforward problems. What is it exactly that you are having difficulties with ?
Determine the absolute extrema of each function on the given interval. Illustrate your results by
sketching the graph of each function.
����f(x) = ��(x − 1)^2�� , 0 ≤ x� ≤ 2
1 answer