To determine if the point (3,8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y \leq 6x - 3 \), we need to check whether the point satisfies each inequality.
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Check the first inequality \( y > x + 5 \):
- Substitute \( x = 3 \) into the inequality: \[ y > 3 + 5 \implies y > 8 \]
- The point (3,8) gives \( y = 8 \), which does not satisfy \( y > 8 \). Therefore, this inequality is not satisfied.
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Check the second inequality \( y \leq 6x - 3 \):
- Substitute \( x = 3 \) into the inequality: \[ y \leq 6(3) - 3 \implies y \leq 18 - 3 \implies y \leq 15 \]
- The point (3,8) gives \( y = 8 \), which satisfies \( y \leq 15 \).
Now, summarizing the results:
- The point (3,8) does not satisfy the first inequality \( y > x + 5 \).
- The point (3,8) does satisfy the second inequality \( y \leq 6x - 3 \).
Thus, the correct response is: No, it is in the solution set for \( y \leq 6x - 3 \), but on the line for \( y > x + 5 \).