To determine if the point (3, 8) is a solution to the simultaneous inequalities \( y > x + 5 \) and \( y \leq 6x - 3 \), we will evaluate each inequality with this point.
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Check the first inequality: \( y > x + 5 \)
Plug in \( x = 3 \) and \( y = 8 \): \[ 8 > 3 + 5 \] \[ 8 > 8 \] This statement is false because 8 is not greater than 8. Thus, the point (3, 8) does not satisfy this inequality.
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Check the second inequality: \( y \leq 6x - 3 \)
Again, plug in \( x = 3 \) and \( y = 8 \): \[ 8 \leq 6(3) - 3 \] \[ 8 \leq 18 - 3 \] \[ 8 \leq 15 \] This statement is true because 8 is indeed less than or equal to 15.
Since the point (3, 8) satisfies the second inequality but does not satisfy the first inequality, the appropriate response is:
No, it is in the solution set for \( y \leq 6x - 3 \), but on the line for \( y > x + 5 \).