To determine if the point (-1, 1) is a solution to the system of equations, we substitute the given values into each equation and check if the equations hold true.
For the first equation:
x + 2y = 5
Substituting x = -1 and y = 1:
-1 + 2(1) = 5
-1 + 2 = 5
1 = 5
Since the equation is not true, (-1, 1) is not a solution to the first equation.
Now, let's check the second equation:
x - y = -2
Substituting x = -1 and y = 1:
-1 - (1) = -2
-1 - 1 = -2
-2 = -2
The equation holds true, so (-1, 1) is a solution to the second equation.
Since (-1, 1) is only a solution to one of the equations, it is not a solution to the system of equations.
Determine if the point −1,1 is a solution to the system of equations.%0D%0A%0D%0A%0D%0A%0D%0Ax+2y=5%0D%0A%0D%0Ax−y=−2
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