To determine the number of solutions, we can solve the system of equations using a method such as substitution or elimination.
Let's solve the system using elimination:
Multiply the first equation by 11 and the second equation by 3 to make the coefficients of y equal:
-55x + 33y = -99
-60x + 33y = -144
Now subtract the second equation from the first equation to eliminate y:
(-55x + 33y) - (-60x + 33y) = -99 - (-144)
-55x + 33y + 60x - 33y = -99 + 144
5x = 45
x = 9
Substitute the value of x into the first equation to solve for y:
-5(9) + 3y = -9
-45 + 3y = -9
3y = 36
y = 12
So the solution to the system of equations is x = 9 and y = 12. Therefore, the system has exactly one solution.
Determine if the following system of equations has no solutions, infinitely many solutions or exactly one solution.
minus, 5, x, plus, 3, y, equals, minus, 9
−5x+3y=
−9
minus, 20, x, plus, 11, y, equals, minus, 48
−20x+11y=
−48
Answer
Multiple Choice Answers
One SolutionOne Solution
Infinitely Many SolutionsInfinitely Many Solutions
No SolutionsNo Solutions
1 answer