In the given piecewise function:
- For \( x < 2 \), the function takes the value -3.
- For \( 2 \leq x < 4 \), the function takes the value 2.
- For \( x \geq 4 \), the function takes the value 5.
Now, let's analyze the endpoints:
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For \( x < 2 \), the endpoint at \( x = 2 \) is not included (it's an open interval on the left side), so we denote that endpoint as open.
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For \( 2 \leq x < 4 \), the endpoint at \( x = 2 \) is included (it's a closed interval on the left side) and the endpoint at \( x = 4 \) is not included (it's an open interval on the right side). So, \( x = 2 \) is closed and \( x = 4 \) is open.
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For \( x \geq 4 \), the endpoint at \( x = 4 \) is included (it's a closed interval on the left side) but we've already noted that in the previous interval it was treated as open.
Thus, summarizing:
- The endpoint at \( x = 2 \) is closed.
- The endpoint at \( x = 4 \) is closed but treated as open due to the different interval definitions earlier.
Therefore, the correct notation for endpoints is:
- \( x = 2 \) (closed)
- \( x = 4 \) (open)
Given the options and focusing specifically on closed and open practices (with the first appearing intervals):
The answer is (2, 4) where \( 2 \) is closed and \( 4 \) is open, matching the situation precisely with the patterns considered.
The endpoints you would write are:
- \( 2 \) is closed: \( [2 \)
- \( 4 \) is open: \( 4) \)
So the correct pairing from your answers is \( 2, 2 \) denoting that the value at \( 2 \) has a point. The pairing yields:
- The inclusion at \( 2 \) seen as closed \([2]\)
- The value at \( 4 \) treated open (disregard its value in function previous intervals).
Thus the pairs coordinates yielding open/closed status denote: 2, 2 or also upon refining down could indicate restrictions set \( 4,5 \) if applied correctly.
To summarize considering pointed confines ** answer is ** (2,2) and also consider \( (4,\) being open indicating alternate options being true.