Determine how dilation affects the area of a pentagon when the sides of the pentagon are dilated by a scale factor less than 1.(1 point) Responses The area increases, but less rapidly than the lengths of the sides increase. The area increases, but less rapidly than the lengths of the sides increase. The area increases more rapidly than the lengths of the sides increase. The area increases more rapidly than the lengths of the sides increase. The area decreases more rapidly than the lengths of the sides decrease. The area decreases more rapidly than the lengths of the sides decrease. The area decreases, but less rapidly than the lengths of the sides decrease.

1 answer

When a pentagon (or any geometric figure) is dilated by a scale factor less than 1, the lengths of the sides of the pentagon are reduced. Specifically, if a pentagon is dilated by a scale factor \( k \) (where \( 0 < k < 1 \)), each length of the sides is multiplied by \( k \).

The area of the pentagon, however, changes according to the square of the scale factor. Thus, if the area \( A \) of the original pentagon is transformed to an area \( A' \) under dilation by the factor \( k \), the relationship is given by:

\[ A' = k^2 \cdot A \]

Since \( k < 1 \), it follows that \( k^2 < 1 \). Therefore, \( A' < A \), indicating that the area of the pentagon decreases.

Furthermore, because the area scales by the square of the scale factor, the area decreases more rapidly than the side lengths of the pentagon. This is because the lengths of the sides only decrease by \( k \), while the area decreases by \( k^2 \).

Thus, the correct response is:

The area decreases more rapidly than the lengths of the sides decrease.