Determine h'(x) for h(x)= [x/(1-x)]^2

Answer 1

h(x) = [x/(1-x)]^2 = x^2 * (1-x)^-2

h'(x) = 2x/(1-x)^2 +(-2)(-1)*x^2*(1-x)^-3
= 2x/(1-x)^2 + 2x^2/(1-x)^3