Determine for solid manganese (Mn) the following:

Question

What is the atomic density (atoms/m) along the [110] direction of the Mn crystal?

What are the number of nearest neighbors around an atom in the Mn crystal?

Calculate the interplanar spacing (m) between {220} planes in the Mn crystal.

Answer 1

For molibdenium

We see from the PT that Mo is a BCC material, so the face diagonal [011] has 2⋅(12) atoms over a distance of 2√a.

The value of the lattice parameter a can be found in the same manner as the previous problem (noting that the BCC structure has only 2 atoms per unit cell rather than 4). Thus,

1 atom2√a=12√(2VmolarNAv)1/3=2.24×107

Answer 2

2.44e9

Answer 3

gg is right