well, f(-x) = -x/(-x-1) = x/(x+1) ≠ -f(x)
so no symmetry about (0,0)
Also, f(-x) ≠ f(x), so no symmetry about the y-axis
f^-1(x) = x/(x-1), so there is symmetry about the line y=x.
See
http://www.wolframalpha.com/input/?i=inverse+x%2F%28x-1%29
determine all symmetries of the function g(x)=x/x-1
2 answers
ok I get it. But what's the actual answer