Desperado, a roller coaster built in Nevada, has a vertical drop of 68.6 m. The roller coaster is designed so that

the speed of the cars at the end of this drop is 35.6 m/s. Assume the cars are at rest at the start of the drop.
What percent of the initial mechanical energy is dissipated by friction?

1 answer

To determine the percentage of initial mechanical energy that is dissipated by friction, we need to calculate the initial potential energy and the final kinetic energy of the roller coaster cars.

  1. Calculate the initial potential energy (PE_initial): The potential energy at the top of the drop can be calculated using the formula: \[ PE_{\text{initial}} = mgh \] where:

    • \(m\) is the mass of the roller coaster cars (which will cancel out later),
    • \(g\) is the acceleration due to gravity (\(9.81 , \text{m/s}^2\)),
    • \(h\) is the height of the drop (68.6 m).
  2. Calculate the final kinetic energy (KE_final): The kinetic energy at the bottom of the drop can be calculated using the formula: \[ KE_{\text{final}} = \frac{1}{2} mv^2 \] where:

    • \(v\) is the speed at the end of the drop (35.6 m/s).
  3. Initial potential energy (using mass \(m\)): \[ PE_{\text{initial}} = m \cdot 9.81 \cdot 68.6 \]

  4. Final kinetic energy (using mass \(m\)): \[ KE_{\text{final}} = \frac{1}{2} m (35.6)^2 \]

  5. Now we will simplify the expressions: The potential energy simplifies to: \[ PE_{\text{initial}} = m \cdot 9.81 \cdot 68.6 \approx 672.616 m \] The kinetic energy simplifies to: \[ KE_{\text{final}} = \frac{1}{2} m \cdot (35.6)^2 = \frac{1}{2} m \cdot 1267.36 \approx 633.68 m \]

  6. Determine how much mechanical energy is dissipated by friction: The initial mechanical energy is equal to the initial potential energy: \[ E_{\text{initial}} = PE_{\text{initial}} = 672.616 m \] The final mechanical energy is equal to the final kinetic energy: \[ E_{\text{final}} = KE_{\text{final}} = 633.68 m \]

  7. Calculate the energy dissipated by friction: \[ E_{\text{dissipated}} = E_{\text{initial}} - E_{\text{final}} = 672.616 m - 633.68 m = 38.936 m \]

  8. Now let's find the percentage of energy dissipated: \[ \text{Percentage dissipated} = \frac{E_{\text{dissipated}}}{E_{\text{initial}}} \times 100 = \frac{38.936 m}{672.616 m} \times 100 \]

    The mass \(m\) cancels out: \[ \text{Percentage dissipated} = \frac{38.936}{672.616} \times 100 \approx 5.79% \]

Final result: Approximately 5.79% of the initial mechanical energy is dissipated by friction.