Deshaun is looking up at a flag that is 50 feet away from him at an angle of elevation from ground level of

35° What is the flagpole's height, x, and the distance between Deshaun and the top of the flagpole, y? (1 point)
• x = 71.41 ft. and y = 87.17 ft.
• x = 35.01 ft. and y = 61.04 ft.
• x = 61.04 ft. and y = 35.01 ft.
• x = 35.01 ft. and y = 35.70 ft.

1 answer

To find the height of the flagpole (x) and the distance from Deshaun to the top of the flagpole (y), we can use some trigonometry.

Given:

  • Distance from Deshaun to the base of the flagpole = 50 feet
  • Angle of elevation = 35°

Step 1: Find the height of the flagpole (x)

We can use the tangent function, which relates the height of the flagpole to the distance from Deshaun:

\[ \tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}} \]

In this case, the "opposite" side is the height of the flagpole (x) and the "adjacent" side is the distance from Deshaun to the base of the flagpole (50 ft):

\[ \tan(35°) = \frac{x}{50} \]

To solve for x:

\[ x = 50 \cdot \tan(35°) \]

Calculating \( \tan(35°) \):

\[ \tan(35°) \approx 0.699 \]

So,

\[ x \approx 50 \cdot 0.699 \approx 34.95 \text{ feet} \]

Step 2: Find the distance from Deshaun to the top of the flagpole (y)

To find this, we can use the sine function:

\[ \sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}} \]

Here, the hypotenuse is the distance from Deshaun to the top of the flagpole (y) and the opposite remains x.

Thus,

\[ \sin(35°) = \frac{x}{y} \]

We can rearrange this to solve for y:

\[ y = \frac{x}{\sin(35°)} \]

Calculating \( \sin(35°) \):

\[ \sin(35°) \approx 0.5736 \]

Substituting the value of x:

\[ y \approx \frac{34.95}{0.5736} \approx 61.00 \text{ feet} \]

Summary of Results

The calculations yield:

  • Height of the flagpole \( x \approx 34.95 \text{ feet} \)
  • Distance to the top of the flagpole \( y \approx 61.00 \text{ feet} \)

Conclusion

The closest option that matches our calculations is:

x = 35.01 ft. and y = 61.04 ft.