Your first step should have been to simplify the expression:
(x^2+x-6)/(x^2-9)
= (x+3)(x-2)/( (x+3)(x-3) )
= (x-2)/(x-3), x ≠ 3
take over
Describe the vertical asymptote and hole for the graph of (x^2+x-6)/(x^2-9).
a. asymptote: x=2; hole: x=-3
b. asymptote: x=3; hole: x=2
c. asymptote: x=-3; hole: x=3
d. asymptote: x=3; hole: x=-3
I know that it has to either be b or d because the asymptote is x=3. Can someone please help with the rest?
1 answer