Describe the steps (and the glassware used) to making 100 mL of a 1 M Tris pH 7.8.

Answer 1

Let's see.
M = mols/L; therefore,
# mols = M x L
You have M = 0.100 and you have L - 0.100 so you want 0.01 mols of the base and 0.01 mols of the salt (the acid) (since the problem states you want an equimolar solution of base and acid.
After you know mols, then mols = grams/molar mass. You know molar mass and you know the mols, calculate grams of the base and grams of the salt (acid). Voila!......"by.DRbob222"

Answer 2

But does the problem say equimolar. The pKa I looked up is 8.1 and you want pH of 7.8 so that isn't equimolar. Close but not quite.