Describe the preparation of 100 mL of 6.0 M HCL from a concentrated solu-tion that has a specific gravity of 1.18 and is 37% (w/w) HCl (36.5 g/mol).

Answer 1

First you determine by calculation the molarity of the 37% solution.
1.18 g/mL x 1000 mL x 0.37 x (1/36.5) = ? mols/L = M which I will call M1.
Thsn use the dilution formula of
M1 x mL1 = M2 x mL2
M1 from the above calculation, mL1 = solve for this.
M2 = 6 M
mL2 = 100 mL
Substitute and solve for mL1. Pipet the volume mL1 from the concentrated solution and add it to a 100 mL volumetric flask. Add distilled or deionized water to the 100 mL flask until the water level reaches the mark on the neck of the flask. Stopper, mix thoroughly, label. Done.