Describe the preparation of 100 ml 6.00 M HCL acid from a concentrated solution that has a specific gravity of 1.18 and 37/100

1 answer

Assuming 37/100 means 37percent w/w.
you need 6M*.100 moles HCL or .6moles, or .6*36.46=21.8 grams HCl
if the concentrated acid is 37 percent w/w, then you need mass HCL=21.8/.37 grams =58.9 grams HCL concentrate.
volume HCL cocentrate= 58.9/1.18 ml = 49.9 ml
description: in the fume hood, pipet off 49.9 ml cocentrated acid,
add that acid to 40 ml water, slowly, stiring. When all is added, add water to the 100 ml mark of solution. Label the solution.