Describe the end behavior of the function y=logx

Question

.(1 point)
Responses

As x→−∞
, y→−∞
, and as x→∞
, y→∞
.
As x right arrow negative infinity , y right arrow negative infinity , and as x right arrow infinity , y right arrow infinity .

As x→0+
, y→∞
, and as x→∞
, y→−∞
.
As x right arrow 0 superscript positive baseline , y right arrow infinity , and as x right arrow infinity , y right arrow negative inifinity .

As x→−∞
, y→−∞
, and as x→0
, y→∞
.
As x right arrow negative infinity , y right arrow negative inifinity , and as x right arrow 0 , y right arrow infinity .

As x→0+
, y→−∞
, and as x→∞
, y→∞
.

Answer 1

The correct description of the end behavior of the function \( y = \log x \) is:

As \( x \to 0^+ \), \( y \to -\infty \), and as \( x \to \infty \), \( y \to \infty \).

This means that as \( x \) approaches 0 from the positive side, the value of \( y \) decreases without bound (approaching negative infinity), and as \( x \) increases towards positive infinity, the value of \( y \) also increases without bound (approaching positive infinity).